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The unit of permitivity of free space ep...

The unit of permitivity of free space `epsilon_(0)` is

A

coulomb/newton-metre

B

newton-`"metre"^(2)`/coulomb

C

`"coulomb"^(2)`//newton-`"metre"^(2)`

D

coulomb/(newton-`"metre"^2`

Text Solution

Verified by Experts

The correct Answer is:
C
`"coulomb"^(2)`//newton-`"metre"^(2)`
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