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The repulsive force between two magnetic...

The repulsive force between two magnetic poles in air is `9 xx 10^(-3)` N. if the two poles are equal in strength and are separated by a distance of 10 cm , calculate the pole strength of each pole .

Text Solution

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The force between two poles are given by `vecF=k""(q_(m_A) q_(m_B))/(r^(2))`
The magnitude of the force is F`=k(q_(m_A)q_(m_B))/(r^(2))`
Given : `F= 9 x x10^(-3)N, r=10 cm = 10 xx 10^(-2) m`
Therefore , `9 xx 10^(-3) = 10^(-7) xx (q_(m)^(2))/((10 xx 10^(-2))^(2))implies q_m= 30NT^(-1)`
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