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A circular antenna of area 3 m^(2) is i...

A circular antenna of area `3 m^(2)` is installed at a place in Madurai. The plane of the area of antenna is inclined at ` 47^(@)` with the direction of Earth's Magnetic field. If the magnitude of Earth's field at that place is `40773.9 nT` find the magnetic flux linked with the antenna .

Text Solution

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`B=40773.9 nT , theta = 90^(@) - 47^(@) = 43^(@) , A = 3m^(2)`
We know that , `Phi_B= BA cos theta `
`B= 40773.9 xx 10^(-9) xx 3 xx cos 43^(@) = 40.7739 xx 10^(-6) xx 3 xx 0.7314= 89. 47 xx 10^(-6) Wb`
` Phi_B= 89.47 mu ` Wb
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