Show the time period of oscillation when a bar magnet is kept in a uniform magnetic field is T = `2pi sqrt((l)/(p_(m)B))` . In second, where I represents moment of inertia of the bar magnet, `p_(m)` is the magnetic moment and is the magnetic field.

Derive an expression for potenstial energy of bar magnet in a uniform magnetic field.

A magnetic needle is kept in a non-uniform magnetic field. It experiences

To measure the magnetic moment of a bar magnet, one may use

Draw the magnetic field lines for a bar magnet.

A bar magnet of mass 100 g, length 7.0 cm, width 1.0 cm and height 0.50 cm takes pi/2 seconds to complete an oscillation in an oscillation magnetometer placed in a horizontal magnetic field of 25 muT . (a) Find the magnetic moment of the magnet. (b) If the magnet is put in the magnetometer with its 0.50cm edge horizontal, what would be the time period?

A bar magnet of magnetic moment M is cut into two parts of equal length. The magnetic moment of either part is

The dimension of magnetic field in M, L, T and C (coulomb) is given as