An electron is accelerated through a potential difference of 81V. What is the de Broglie wavelength associated with it? To which part of electromagnetic spectrum does this wavelength corresspond ?

Explanation

de-Broglie wavelength of an electron beam accelerated through a potential difference of V volts is
`lambda = h/sqrt(2MeV) = 1.23/sqrtVnm`
`V = 81V, " so " lambda= 1.23/sqrt81xx 10^(-9)m = 0.1366 xx 10^(-9)m`
`lambda = 1.36 Å`
X-ray is the part of electromagnetic spectrum does this wavelength coresponds. X-ray has the wavelengths ranging from about `10^(-8)" to " 10^(-12)m`.