" Luts the curve "y^(2)=x+2" at "A" and "B" and point on the line "P" is "(sqrt(3),0)" then "1/PA.P

If the line y-sqrt(3)x+3=0 cuts the curve y^(2)=x+2 at A and B and point on the line P is (sqrt(3), 0) then PA. PB =

If the line y=sqrt(3)x+3=0 cuts the curve y^(2)=x+2 at A ,B and the point P(sqrt(3) ,0) .Then |PA*PB| =

If the line y-sqrt(3)x+3=0 cuts the parabola y^(2)=x+2 at A and B, then find the value of PA.PB { where P=(sqrt(3),0)}

If the line y-sqrt(3)x + 3=0 cuts the parabola y^2=x + 2 at A and B, then find the value of PA.PB(where P=(sqrt(3),0)

If the line y-sqrt(3)x + 3=0 cuts the parabola y^2=x + 2 at A and B, then find the value of PA.PB(where P=(sqrt(3),0)

If the normals to the curve y=x^(2) at the points P,Q and R pas thrugh the points (0,(3)/(2)), then find circle circumsecribing the triangle PQR.

A line is drawn form A(-2,0) to intersect the curve y^(2)=4x at P and Q in the first quadrant such that (1)/(AP)+(1)/(AQ) sqrt(3)(B) sqrt(2)(D)>(1)/(sqrt(3))

P is a variable point on the curve y= f(x) and A is a fixed point in the plane not lying on the curve. If PA^(2) is minimum, then the angle between PA and the tangent at P is

P is a variable point on the curve y= f(x) and A is a fixed point in the plane not lying on the curve. If PA^(2) is minimum, then the angle between PA and the tangent at P is