If `P=3x^3+3x^2+3x+3` and `Q=3x^2-3x+3,` then `P-Q=` `3x^3` (b) `3x^3+6x^2+6x+6` `6x^2+6x+6` (d) `3x^3+6x`

If P=3x^3+3x^2+3x+3 and Q=3x^2-3x+3, then P-Q= (a) 3x^3 (b) 3x^3+6x^2+6x+6 (c) 6x^2+6x+6 (d) 3x^3+6x

If P(x)= x^3- 6x^2 + 11x-1 then find: p(x)-p(3)

p(x) = 3x^(3) - 2x^(2) + 6x - 5 then p(2) = ………………

x^(3)-6x^(2)+3x+10

From the sum of 6x^(4) - 3x^(3) + 7x^(2) - 5x + 1 and -3x^(4) + 5x^(3) - 9x^(2) + 7x - 2 subtract 2x^(4) - 5x^(3) + 2x^(2) - 6x - 8

12x - [3x^(2) + 5x^(2) - {7x^(2) - (4 - 3x - x^(3)) + 6x^(3)}-3x]

If =5x^(3)+3x^(2)-4x+1,Q=3x^(3)+5x2+3x-8 and R=6x^(3)-4x^(2)-7x+3 find (P+Q)-R

((2x^(4)-3x^(3)-3x^(2)+6x-2)/(x^(2)-2))