The hydrolysis of optically active 2-bromobutane with aqueous NaOH result in the formation of :

Assertion (A ) S_(N) 1 hydrolysis of optically active -2 bromooctane results in the formation of (+-) - octan -2-ol . Reason (R ) The reation proceeds through a planar carbocation which can be attacked by the nucleophile from either side. The correct answer is

Elimination of bromine from 2-bromobutane results in the formation of

Elimination of bromine from 2-bromobutane results in the formation of:

Elimination of bromine from 2- bromobutane results in the formation of