A heavy truck and bike are moving with the same kinetic energy . If the mass of the truck is four times that of the bike , then calculate the ratio of their momenta . (Ratio of momenta = 1:2)

Explanation

Given : Let `m_(1),m_(2)` are masses of truck and bike.
`m_(1)=4m_(2)`
Here kinetic energies of both truck and bike are same
`m_(1)v_(1)^(2)=m_(2)v_(2)^(2)`
`4m_(2)v_(1)^(2)=m_(2)v_(2)^(2)`
`(v_(1))/(v_(2))=(1)/(2)`
`v_(2)=2v_(1)`
`"Ratio of momenta: "(p_(1))/(p_(2))=(m_(1)v_(1))/(m_(2)v_(2))=(4m_(2))/(m_(2)).(v_(1))/(2v_(1))`
`=2`
`p_(1):p_(2)=2:1`