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For a person with hypermeteropia, the ne...

For a person with hypermeteropia, the near point has moved to 1.5 m. calculate the focal length of the correction lens in order to make his eyes normal.

Text Solution

Verified by Experts

Given that , d= 1.5m, D = 25 cm =0.25m (For anormal eye The focal length of the correction lens is
`f=(d xxD)/(d-D)`
`=(1.5xx0.25)/(1.5-0.25)`
`=(0.375)/(1.25)=0.3m`
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