(a) (i) Calculate the number of molecules in 10 mole of `H_(2)`.
(11) Calculate the number of moles in 1 kg of `CaCO_(3)`
(iii) Calculate the volume of 14 g of `N_(2)` gas.

Explanation

(i) n - 10 mole, `N_(A)=6.023xx10^(23)`
  Number of molecules =`10xx6.023xx10^(23)` (ii)Number of moles n = `(mass (w) in gram)/(molar mass (w) in g mol^(-1))`
  W = 1 kg = 1000 g
M = 100 g `mol^(-1)`In-?
`n=(W)/(M)=(1000)/(100)=10mol`
(iii)28 g (1 mole) of `N_(2)` gas occupies 22.4 litres
14 g of `N_(2)` gas occupies
`(22.4)/(28)xx14=(22.4)/(2)` =11.2 litres