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A piece of wire of resistance 20 Omega i...

A piece of wire of resistance `20 Omega` is drawn out so that length is increased to twice its original length. Calculate the new resistance.

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A piece of wire of resistance 10 ohm is drawn out so that its length is increased to three times its original length. Calculate the new resistance.

A piece of wire of resistance 10 ohm is drawn out so that its length is increased to three times its original length. Calculate the new resistance.

Knowledge Check

  • A wire of resistance R is stretched to three times its original length. The new resistance is

    A
    3R
    B
    9R
    C
    `R//3`
    D
    `R//9`

  • If a wire of resistance R is stretched to twice its original length, the new resistance of the wire will be:

    A
    `R/2`
    B
    `2R`
    C
    `4R`
    D
    `R/4`

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    (i) A piece of wire of resistance 10 ohm is drawn out so that its length is increased to three times its original length. Calculate the new resistance. (ii) What is co-efficient of cubical expansion?

    A wire of resistance 4 Omega is drawn (a) to twice its original length, (b) by twice its original length. Calculate the new resistance in each case.

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    In the determination of internal resistance of a cell of e.in.f. 1.5 V with potentiometer, the balancing length is 75 cm in the open circuit and when a resistance of 10 Omega is used the balancing length is found to be 65 cm. Calculate the internal resistance of the cell.

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