Home
Class 10
PHYSICS
A piece of wire of resistance 20 Omega i...

A piece of wire of resistance `20 Omega` is drawn out so that length is increased to twice its original length. Calculate the new resistance.

Promotional Banner

Topper's Solved these Questions

  • SAMPLE PAPER - 12

    FULL MARKS|Exercise PART - IV|6 Videos
  • SAMPLE PAPER - 12

    FULL MARKS|Exercise PART - II|10 Videos
  • SAMPLE PAPER - 10

    FULL MARKS|Exercise PART - III|16 Videos
  • SAMPLE PAPER - 14

    FULL MARKS|Exercise PART-IV (ANSWER ALL THE QUESTIONS)|6 Videos

Similar Questions

Explore conceptually related problems

A piece of wire of resistance 10 ohm is drawn out so that its length is increased to three times its original length. Calculate the new resistance.

(i) A piece of wire of resistance 10 ohm is drawn out so that its length is increased to three times its original length. Calculate the new resistance. (ii) What is co-efficient of cubical expansion?

A wire of resistance R is stretched to three times its original length. The new resistance is

A wire of resistance 4 Omega is stretched to twice its original length.The resistance of stretched wire would be

If a wire of resistance R is stretched to twice its original length, the new resistance of the wire will be:

In the determination of internal resistance of a cell of e.in.f. 1.5 V with potentiometer, the balancing length is 75 cm in the open circuit and when a resistance of 10 Omega is used the balancing length is found to be 65 cm. Calculate the internal resistance of the cell.