Explain the experiment of measuring the real and apparent expansion of a liquid with a neat diagram.

Explanation

When the temperature of a gas is kept constant, the volume of a fixed mass of gas is inversely proportional to its pressure. `P prop 1 //V`
(ii). (i) To start with , the liquid whose real and apparent expansion is to be determined is poured in a container up to level. Mark this level as `L_1`
(ii) Now, heat the container and the liquid using a burner as shown in the figure Initially , the container and the liquid using a burner as shown in the figure Initially, the container receives the termal energy and it expands.
(iii) As a result, the volume of the liquid apperas to have reduced. Mark this reduced level of liquid as `L_(2)`.

On further heating, the thermal energy supplied to the liquid through the container results in the expansion of the liquid. Hence, the level of liquid rises to `L_3`. Now, the difference between the levels `L_1` and `L_3` is called as apparent expansion, and the difference between the levels `L_2`, and `L_3` is called real expansion. The real expansion is always more than that of apparent expansion.
Real expansion `=L_3 -L_2`
Apparent expansion `= L_3 -L_1`