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A current carrying conductro of certain ...

A current carrying conductro of certain length, kept perpendicular to the magnetic field experiences a force F. What will be the force if the current is increased four times, length is halved and magnetic field is tripled?

Text Solution

Verified by Experts

`F=1LB=(4I)xx(L//2)xx(3B)=6F`
Therefore, the forces inreases six times
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