x के लिए हल कीजिए: `1/(a+b+x)=(1)/(a)+(1)/(b)+(1)/(x)`

Solve: (1)/(a+b+x)=(1)/(a)+(1)/(b)+(1)/(x)

Solve for x : (1)/(a + b + x) = (1)/(a) + (1)/(b) + (1)/(x) , a ne b ne 0 , x ne 0 , x ne -(a + b)

(1)/(x+a)+(1)/(x+b)=(1)/(x+a+b)+(1)/(x)

Solve for 'x' : (1)/(a+b+x)=(1)/(a)+(1)/(b)+(1)/(x) " " a != 0, b!=0, x !=0

Solve the equations : (1)/(a+b-x)=(1)/(a)+(1)/(b)-(1)/(x)

Simplify : : ( ( x+(1)/(y)) ^(a) ( x-(1)/(y))^(b))/((y+(1)/(x))^(a) (y-(1)/(x))^(b))

निम्न समीकरण को हल कीजिए - tan^(-1)(x-1)+tan^(-1)(x)+tan^(-1)(x+1)=tan^(-1) 3 x

Solve: 1/x-1/(x+b)=1/a-1/(a+b) (x!=0,-b) .

If |(1,1,1),(a,b,c),(a^(3),b^(3),c^(3))| = (a - b) (b - c) (c - a) (a + b + c) , where a,b,c are all different, then the determinant |(1,1,1),((x-a)^(2),(x-b)^(2),(x-c)^(2)),((x-b)(x-c),(x-c)(x-a),(x-a)(x-b))| vanishes when a)a + b + c = 0 b) x = (1)/(3) (a + b + c) c) x = (1)/(2) (a + b + c) d) x = a + b + c