The straight line `x-y-2=0` cuts the axis of `x` at `Adot` It is rotated about `A` in such a manner that it is perpendicular to `a x+b y+c=0` . Its equation is: (a)`b x-a y-2b=0` (b) `a x-b y-2a=0` (c)`b x+a y-2b=0` (d) `a x+b y+2a=0`

A straight line through A(2, 1) is such that its intercept between the axis is bisected at A . its equation is: (a) 2x+y-4 = 0 , (b) x + 2y - 4 = 0 , (C) x + 2y - 4 = 0 , (d) x + 2y - 2 = 0

Find the equation of the tangent line to the curve y=(3x^2-1)/x at the point (1,2) is (a) 4x-y-1=0 (b) 4x+y+2=0 (c)x-y-1=0 (d) 4x-y-2=0

The equation to the normal to the curve y=sinx at (0,\ 0) is x=0 (b) y=0 (c) x+y=0 (d) x-y=0

The equation of the line AB is y = x . If A and B lie on the same side of the line mirror 2x-y = 1 , then the equation of the image of AB is (a) x+y-2=0 (b) 8x+y-9=0 (c) 7x-y-6=0 (d) None of these

Given ABCD is a parallelogram wilth vertices as A(1,2),B(3,4) and C(2,3) . Then the equation of line AD is (A) x+y+1=0 (B) x-y+1=0 (C) -x+y+1=0 (D) x+y-1=0

Two straight lines are perpendicular to each other. One of them touches the parabola y^2=4a(x+a) and the other touches y^2=4b(x+b) . Their point of intersection lies on the line. x-a+b=0 (b) x+a-b=0 x+a+b=0 (d) x-a-b=0

A line intersects x-axis at A(2, 0) and y-axis at B(0, 4) . A variable lines PQ which is perpendicular to AB intersects x-axis at P and y-axis at Q . AQ and BP intersect at R . Locus of R is : (A) x^2 + y^2 - 2x + 4y = 0 (B) x^2 + y^2 + 2x + 4y = 0 (C) x^2 + y^2 - 2x - 4y=0 (D) x^2 + y^2 + 2x - 4y = 0

A line intersects x-axis at A(2, 0) and y-axis at B(0, 4) . A variable lines PQ which is perpendicular to AB intersects x-axis at P and y-axis at Q . AQ and BP intersect at R . Image of the locus of R in the line y = - x is : (A) x^2 + y^2 - 2x + 4y = 0 (B) x^2 + y^2 + 2x + 4y = 0 (C) x^2 + y^2 - 4y = 0 (D) x^2 + y^2 + 2x - 4y = 0

The image of line 2x+y=1 in line x+y+2=0 is : (A) x+2y-7=0 (B) 2x+y-7=0 (C) x+2y+7=0 (D) 2x+y+7=0