Nitro glycerine is used as a explosive. The equation for the explosive reaction is
`underset((l))(4C_(3)H_(5)((NO_(3)))_(3))rarr underset((g))(12CO_(2))+underset((l))(10H_(2)O)+underset((g))(6N_(2))+underset((g))(O_(2))`
`("Atomic mass of C = 12, H = 1, N = 14, O = 16")`
(i) How many moles does the equation show for (a) Nitroglycerine (b) gas molecules produced?
(ii) How many moles of gas molecules are obtained from 1 mole of nitroglycerine?
(iii) What is the mass of 1 mole of nitroglycerine?

Explanation

(i) 4 moles of Nitroglycerine
(ii) 4 moles of Nitroglycerine produce 19 moles of gas molecules
`therefore" 1 mole of Nitroglycerine produces "19//4="4.75 moles"`
(iii) Mass of 1 mole of Nitroglycerine `C_(3)H_(5)(No_(3))_(3)`
`{:("Atomic mass of C ",=, 12),("Atomic mass of 3(C )"=3xx12,=,36),("Atomic mass of 5(H)"=5xx1,=,5),("Atomic mass of 3(N)"=3xx14,=,42),("Atomic mass of 9(O)"=9xx16,=,144),(,,""ulbar("227g")):}`
Mass of 1 mole of Nitroglycerine = 227g