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"i s"sinh^(- 1)(2)+sinh^(- 1)(3)=x thcos...

`"i s"sinh^(- 1)(2)+sinh^(- 1)(3)=x thcosh(x)`

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is sinh^(-1)(2)+sinh^(-1)(3)=xth cosh(x)

If sinh^(-1)2+sinh^(-1)3=x rArr cos hx=

sinh^(-1)2+sinh^(-1)3=x rArr cosh x= then

sinh^(-1)(2^(3//2))=

cosh^(4)(x)-sinh^(4)(x)=

The value of sinh^(-1)(3)

int (sinh x )/(1+ sinh^(2)x) dx=

sinh(cosh^(-1)x)=

int(dx)/(sinh^(2)x cosh^(2)x)