Find `tan 20^(@) + tan40^(@) + sqrt(3)tan20^(@)tan40^(@)`.

tan 20^(@) + tan40^(@) + sqrt(3).tan 20^(@).tan 40^(@)=

A =(cos 9^(@) - sin 9^(@))/(cos 9^(@) + sin 9^(@)) , B = (cos 21^(@) + sin 21^(@))/(cos21^(@) -sin21^(@)) and C= tan 20^(@) + tan40^(@) + sqrt(3)tan20^(@) tan40^(@) then descending order is:

tan20^(@)+tan40^(@)+sqrt(3)tan20^(@).tan40^(@)=?

tan 20^(@) + tan40^(@) + sqrt(3).tan 20^(@).tan 40^(@)= ................... A) (1)/(sqrt3) B) sqrt3 C) -(1)/(sqrt3) D) -sqrt3

The value of tan 40^(@) + tan 20^(@) + sqrt(3) tan 20^(@) tan 40^(@) is equal to

The value of tan 40^(@) + tan 20^(@) + sqrt(3) tan 20^(@) tan 40^(@) is

A=(cos9^(@)-sin9^(@))/(cos9^(@)+sin 9^(@)), B=(cos21^(@)+sin21^(@))/(cos21^(@)-sin21^(@)) and C=tan 20^(@)+tan 40^(@)+sqrt(3)tan20^(@)tan40^(@) then descending order is

tan20^(@)-tan80^(@)+sqrt(3)tan20^(@)tan80^(@)=

The value of tan20^(@)+tan40^(@)+sqrt(3)tan20^(@)tan40^(@) is