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If sqrt2 sec theta + tan theta = 1, then...

If `sqrt2 sec theta + tan theta = 1`, then the general value of `theta` is

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`(sqrt(2)// cos theta)+sin theta// cos theta=1" "( :' cos theta ne 0)`
or `cos theta- sin theta=sqrt(2)`
`rArr (1//sqrt(2)) cos theta-(1//sqrt(2)) sin theta=1`
`rArr cos (theta+pi//4)=1= cos theta`
`rArr theta+(pi//4)=2 n pi`
`rArr theta=2n pi-(pi//4), n in Z`
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