The foci of an ellipse are S(-1,-1), S'(0,-2) its e=1/2, then the equation of the directrix corresponding to the focus S is

The foci of the hyperbola are S(-3,-2), S' (5,6) If its e=2 then the equation of its directrix corresponding to focus S is :

The foci of an ellipse are S(3,1) and S'(11,5) The normal at P is x+2y-15=0 Then point P is

A parabola with focus S=(1,2) touches both the axes then the equation to directrix is

Foci of an ellipse are at S(1,7),S'(1,-3) .The point P is on the ellipse such that SP=7,S'P=5 .then the equation of the ellipse is

Let two foci of an ellipse be S_(1)(2,3) and s_(2)(2,7) and the foot of perpendicular drawn from S1 upon any tangent to the ellipse be (-1,1) . If e be the eccentricity of ellipse and R be the radius of director circle of auxiliary circle of ellipse, then find the value of (eR^(2))/(2)

If for a rectangular hyperbola a focus is (1,2) and the corresponding directrix is x+y=1 then the equation of the rectangular hyperbola is

Find the equation of the ellipse whose foci are at (pm 1, 0) and e=1/2.

One the x-y plane,the eccentricity of an ellipse is fixed (in size and position) by 1) both foci 2 both directrices 3 )one focus and the corresponding directrix 4 ) the length of major axis.