A ray light along the line `x=3` is refiected at the ellipse `(x^2)/25+(y^2)/16=1.` The slope of the refiected ray is

Foci of the ellipse 16x^(2)+25y^(2)=400 are

The straight line x+y=a will be a tangent to the ellipse (x^(2))/(9)+(y^(2))/(16)=1 if a=

The equation of the directrices of the ellipse ((x-2))/(25)+((y-3)^(2))/(16)=1 are

An incident ray is coming along the straight line y=4 and it strikes the parabola y^(2)=4x, then equation of the reflected ray is

The line x+14y=25 is the polar of the ellipse x^(2)+4y^(2)=25. Find coordinates of the pole.

If a ray travelling the line x = 1 gets reflected the line x+y=1 then the equation of the line along which the reflected ray travels is

The line 3x+5y=k touches the ellipse 16x^(2)+25y^(2)=400 ,if k is

If a ray of light incident along the line 3x+(5-4sqrt(2))y=15 gets reflected from the hyperbola (x^(2))/(16)-(y^(2))/(9)=1, then its reflected ray goes along the line.x sqrt(2)-y+5=0 (b) sqrt(2)y-x+5=0sqrt(2)y-x-5=0( d) none of these