In acidic medium,potassium manganate undergoes disproportionation according to equation.
`3MnO_(4)^(2-)+4H^(+)longrightarrow2MnO_(4)^(-)+MnO_(2)+2H_(2)O`
Equivalent weight of `K_(2)MnO_(4)` will be (Mol.wt.of `K_(2)MnO_(4)`=M)

In acidic medium, potassium manganate undergoes disproportionation according to equation.\(3MnO_{4}^{2-}+4H^{+}\rightarrow 2MnO_{4}^{-}+MnO_{2}+2H_{2}O\) Equivalent weight of \(K_{2}MnO_{4}\) will be (Mol.wt.of \(K_{2}MnO_{4}\)=M)

The equation 3MnO_4^(2-)+4H^(+)to2MnO_4^(-)+MnO_2+2H_2O represents

The chemical name of K_(2)MnO_(4) is -

In the reaction MnO_(4)^(-)+SO_(3)^(-2)+H^(+)rarrSO_(4)^(-2)+Mn^(2+)+H_(2)O

Write the disproportionate reaction of MnO_(4)^(2-) ?

In acidic medium MnO_(4)^(2-)

Oxidation number of Mn in K_(2)MnO_(4) is