Length of latusrectum of the ellipse S=0 if b>a is

Question Stimulus :- The length of latusrectum of the ellipse 9x^2+4y^2=1 is-

The vertices of the triangle ABC are A(0, 0), B(3, 0) and C(3, 4) , where A and C are foci of an ellipse and B lies on the ellipse. If the length of the latus rectum of the ellipse is (12)/(p) units, then the vlaue of p is

the length of the latusrectum of the ellipse 3x^(2) + y^(2) = 12 . Is

the length of the latusrectum of the ellipse 5x^(2) + 9x^(2)=45, is

if the line x- 2y = 12 is tangent to the ellipse (x^(2))/(b^(2))+(y^(2))/(b^(2))=1 at the point (3,(-9)/(2)) then the length of the latusrectum of the ellipse is

If the length of the latusrectum of the ellipse x^(2) tan^(2) theta + y^(2) sec^(2) theta = 1 is 1/2, then theta =

Let S and S' be the foci of the ellipse and B be any one of the extremities of its minor axis. If DeltaS'BS=8sq. units, then the length of a latus rectum of the ellipse is

If the length of the eccentricity of an ellipse is (3)/(8) and the distance between the foci is 6 units, then the length of the latus rectum of the ellipse is

Eccentricity of an ellipse is (sqrt(3))/(2) .Find the length of latus rectum of the ellipse , (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 (length of semi major axis is 12 units).