Potential energy of a system of charges `q_(1)` and `q_(2)` which are separated by a distance `r` is ?

Find out potential energy of the two point charge system having charges q_(1) and q_(2) separated by distance r.

Two point charges Q and - Q //4 are separated by a distance X . Then .

Deduce an expression for the potential energy of a system of two point charges q_1 and q_2 located at positions r_1 and r_2 respectively in an external field (vecE)

Three charges -q, +q and -q are placed along a st. line at equal distance , say a. Calculated the potential energy of this system of charges (i) when +q charge is in the middle and (ii) when this charge is at one end.

Two point charges q_(1) = +2 C and q_(2) = - 1C are separated by a distance d . The position on the line joining the two charges where a third charge q = + 1 C will be in equilibrium is at a distance

Write an expression for potential energy of two charges q_(1) and q_(2) at vec(r_(1)) and vec(r_(2)) in a uniform electric field vec(E) .

Two point charges, q_(1)=10xx10^(-8)C and q_(2)=-2xx10-8C are separated by a distance of 60 cm in air. (i) Find at what distance from the 1st charge, q_(1) , would the electric potential be zero. (ii) Also calculate the electrostatic potential energy of the system.