A body starting from rest has an acceleration of `5m//s^(2)`. Calculate the distance travelled by it in `4^(th)` second.

A body starting from rest has an acceleration of 4ms^(-2) . Calculate distance travelled by it in 5th second.

A body starting from rest has an acceleration of 4ms^(-2) . Calculate distnce travelled by it in 5th second.

A body starting from rest has an acceleration of 25ms^(-2) . Find the distance travelled by it in 20^("th") second.

A body starting from rest and has uniform acceleration 8 m//s^(2) . The distance travelled by it in 5^(th) second will be

A body starting from rest has an acceleration of 20 ms^(-2) the distance travelled by it in the sixth second is ...

A body starting from rest is moving with a uniform acceleration of 8m/s^(2) . Then the distance travelled by it in 5th second will be

A body starting from rest is moving with a uniform acceleration of 8m/s^(2) . Then the distance travelled by it in 5th second will be

A particle, starting from rest, moves with constant acceleration 4 ms^(-2). The distance travelled by the particle in 5^(th) second is.

A body starts from rest with uniform acceleration in a st. line, Then distance travelled by body in 3rd and 4th second are in the ratio :