A body falling for 2 seconds covers a distance S equal to that covered in next second. Taking `g = 10m//s^(2),S =`

A body falling for 2 s covers a distance a which is equal to that covered in next l s. If g = 10 ms^ -2 , the distance s is

A body is projected vertically up. What is the distance covered in its last second of upward motion? (g=10 m//s^(2))

A body is projected vertically up. What is the distance covered in its last second of upward motion? (g=10 m//s^(2))

A body is projected vertically up. What is the distance covered in its last second of upward motion? (g=10 m//s^(2))

What distance will a body cover in 20 s travelling at 50 m/s?