Refractive index of a prism is `sqrt(7//3)` and the angle of prism is `60^(@)`. The minimum angle of incidence of a ray that will be tramitted through the prixm is

Refractive index of a prism is sqrt(7//3) and the angle of prism is 60^(@) . The minimum angle of incidence of a ray that will be transmitted through the prism is

Refractive index of a prism is sqrt(7//3) and the angle of prism is 60^(@) . The minimum angle of incidence of a ray that will be transmitted through the prism is

Refractive index of a prism is sqrt((7)/(3)) and the angle of prism is 60^@ . The limiting angle of incidence of a ray that will be transmitted through the prism is approximately

The refractive index of the material of a prism is sqrt((3)/(2)) and the refracting angle is 90^(@) The angle of minimum deviation of the refracted ray by the prism is

The refracting angle of a prism is 60^(@) and the refractive index of its material is sqrt((7)/(3)). Find the minimum angle of incidence of a ray of light falling on one refracting face of the prism such that the emerging ray will graze the other refracting face.

The refractive index of a prism for monochromatic wave is sqrt(2) and its refracting angle is 60^(@) . For minimum deviation the angle of incidence will be

The refractive index of a prism is sqrt(2) and its refractive angle is 60^(@) . If a ray emerge with the minimum angle of deviation then the angle of incidence will be

The refractive index of the material of prism sqrt3, then the angle of minimum deviation of prism is

A prism of refractive index sqrt(2) has refractive angle 60^(@) . Find the angle of incidence so that a ray minimum deviation.