Home
Class 12
PHYSICS
A body of mass 500 gram is rotating ...

A body of mass 500 gram is rotating in a vertical of radius 1 m . What is the difference in its kinetic energies at the top and the bottom of the circle ?

Promotional Banner

Similar Questions

Explore conceptually related problems

A body of mass 1 kg is rotating in a verticle circle of radius 1 m .What will be the difference in its kinetic energy at the top and bottom of the circle ? (g=10m//s^(2))

A body of mass .m. is rotating in a vertical circle of radius .r. with critical speed at the highest point. The difference in its K.E. at the top and bottom is

A body of mass 1 kg is moving in a vertical circular path of radius 1 m. The difference between the kinetic energies at its highest and lowest position is

A body of mass 1 kg is moving in a vertical circular path of radius 1 m. The difference between the kinetic energies at its highest and lowest position is

A body is mass m is rotating in a vertical circle of radius 'r' with critical speed. The difference in its K.E at the top and at the bottom is

A body is mass m is rotating in a vertical circle of radius 'r' with critical speed. The difference in its K.E at the top and at the bottom is