The wavelengths of electron waves in two orbits is 3:5. The ratio of kinetic energy of electrons will be

The wavelength of electron waves in two orbits is 3:5 . The ratio of kinetic energy of electrons wil be

Wavelength of electron waves in two Bohr orbits is in ratio3:5 the ratio of kinetic energy of electron is 25 : x, hence x is :

Wavelength of electron waves in two Bohr orbits is in ratio3:5 the ratio of kinetic energy of electron is 25 : x, hence x is :

The wavelength of electron waves in two orbits (lambda_(1) : lambda_(2))

The electron is moving with a velocity c/3 . The de-Broglie wavelength of electron is observed to be equal to a moving photon. The ratio of kinetic energy of electron to that energy of photon is found to be a:6. Find the value of a.

The wavelength of photon of lambda is equal to the de-Broglie wave length of electron. Show that energy of photon =2lambdamc/hxx kinetic energy of electron .

Kinetic energy of electron in nth orbit is given by

The de-Broglie wavelength of an electron is the same as that of a 50 ke X-ray photon. The ratio of the energy of the photon to the kinetic energy of the electron is ( the energy equivalent of electron mass of 0.5 MeV)