In a car race car `A` takes `t_(0)` time less to finish than car `B` and pases the finishing point with a velocity `v_(0)` more than car `B`. The cars start from rest and travel with constant accelerations `a_(1)` and `a_(2)` . Then the ratio `(v_(0))/(t_(0))` is equal to

In a car race, A takes a time of t s, less than car B at the finish and passes the finishin point with a velocity v more than car B . Assuming that the cars stat from rest and travel with constant accelerations a_(1) and a_(2) . Respectively, show that vsqrt(a_(1) a_(2)t) .

In a car race, car A takes a time of t s less than car B at the finish and passes the finishing point with a velocity v m/s more than the car B. Assuming that the cars start from rest and travel with constant acceleration a_1 and a_2 respectively, velocity v is given by

In a car race, car A takes time t less than car B and passes the finishing point with a velocity v more than the velocity with which car B passes the point. Assuming that the cars start from rest and travel with constant accelerations a_1 and a_2 show that v/t=sqrt(a_1a_2) .

In a car race, car A takes time t less than car B and passes the finishing point with a velocity v more than the velocity with which car B passes the point. Assuming that the cars start from rest and travel with constant accelerations a_1 and a_2 show that v/t=sqrt(a_1a_2) .