Comprehension (Q. No. 6 to Q. No. 8) Let `(x_1, y_1)&(x_2, y_2)` are the solutions of the equation, `(log)_(225)(x)+(log)_(64)(y)=4` and `(log)_x(225)-(log)_y(64)=1` `(log)_(225)x_1dot(log)_(225)x_2=` 2 (b) 4 (c) 6 (d) 8

If (x_(1),y_(1)) and (x_(2),y_(2)) are the solution of the system of equation log_(225)(x)+log_(64)(y)=4 and log_(x)(225)-log_(y)(64)=1, then show that the value of log_(30)(x_(1)y_(1)x_(2)y_(2))=12

If (x_(1),y_(1))&(x_(2),y_(2)) are the solutions of the equaltions,log_(225)(x)+log_(64)(y)=4 and log_(x)(225)-log_(y)(64)=1log_(225)x_(1).log_(225)x_(2)=4 b.log_(225)x_(1)+log_(225)x_(2)=6c|log_(64)y_(1)-log_(64)y_(2)|=2sqrt(5)d*log_(30)(x_(1)x_(2)y_(1)y_(2))=12

IF y' = y/x(log y - log x+1), then the solution of the equation is :

The solutions to the system of equations log_(5)x+log_(27)y=4 and log_(x)5-log_(y)(27)=1 are (x_(1),y_(1)) and (x_(2),y_(2)) then log_(15)(x_(1)x_(2)y_(1)y2) is

Let (x_(0),y_(0)) be the solution of the following equations: (2x)^(ln2)=(3y)^(ln3) and 3^(ln x)=2^(ln y) Then value of x_(0) is:

Let x and y are solutions of the system of equations {log_(8)(1)+log_(3)(x+2)=log_(3)(3-2y) and 2^(x+y)-8^(3-y)=0 The value of (y-x), is

The solution of the differential equation log((dy)/(dx))=4x-2y-2,y=1, where x=1 is

if log_(9)x+log_(4)y=(7)/(2) and log_(9)x-log_(8)y=-(3)/(2) then x+y is

If xy^(2)=4and(log)_(3)((log)_(2)x)+(log)_((1)/(3))((log)_((1)/(2))y)=1 then x equals (a)4(b)8(c)16(d)64