`0.250g` of an element M, reacts with excess fluorine to produce `0.547g` of the hexafluoride `MF_(6)`. What is the elemejnt : `[Cr = 52, Mo = 96, S = 32, Te = 127.6]` .

8.6 g of an element when treated with excess of acid produce 1900ml of H_2 gas STP. The equivalent mass of metal is?

6g of Mg reacts with excess of an acid. The amount of hydrogen produced would be

5.0 g of a certain element X forms 10.0 g of its oxide having the formula X_4O_6 . What is the atomic mass of X

Flourine reacts with uranium to produce uranium hexaflouride , UF_(6) , as represented by this equation U(s) + 3F_(2)(g) to UF_(6)(g) How many fluorine molecules are required to produce 7.04 mg of uranium hexafluoride , UF_(6) , from an excess of uranium? The molar mass of UF_(6) is 352 gm/mol (N_(A)=6xx10^(23))

1.60 g of a metal A and 0.96 g of a metal B when treated with excess of dilute acid, separately, produced the same amount of hydrogen. Calculate the equivalent weight of A if the equivalent weight of B is 12.