The capacitance of a capacitor, filled with two dielectrics of same dimensions but of dielectric constants `K_1 and K_2` respectively as shown will be -

A capacitor is filled with two dielectrics of same dimensions, but of dielectric constants 2 and 3 respectively. Find the ratio of capacitances in the two arrangements shown in Fig.

The space between parallel plate capacitors is filled with four dielectrics of equal dimensions but of dielectric constants K_(1), K_(2), K_(3)andK_(4) respectively. If K is the dielectric constant of a single dielectric that must be filled between capacitor plates to have the same capacitance between A and B. Then we must have

A capacitor of plate area A and separation d is filled with two dielectrics of dielectric constant K_(1) = 6 and K_(2) = 4 . New capacitance will be

Write the capacitance of parallel plate capacitor with medium of dielectric of dielectric constant K.

Give the expression for capacitance of a capacitor when n dielectric slabs of thickness t_1, t_2 ... t_n and dielectric constants k_1, k_2 ... k_n respectively, fills the entire space between the plates.

Air filled capacitor of capacitance 2 muF is filled with three dielectric material of dielectric constant K_(1) = 4, K _(2) = 4 and K_(3) = 6 as shown in the figure . The new capacitance of the capacitor is