The current in `C` is `2 A`. The rate of heat of loss in `A,B` and `C are 1.20, 0.60 and `1.20 J//sec respectively. The emf of the cell [for cell internal resistance = 0] is

The resistance of the four arms A, B, C and D of a wheatstone bridge as shown in the figure are 10 Omega , 20 Omega , 30 Omega and 60 Omega respectively . The emf and internal resistance of the cell are 15 V and 2.5 Omega respectively . If the galvanometer resistance is 80 Omega then the net current drawn from the cell will be

The resistance of the four arms A, B, C and D of a wheatstone bridge as shown in the figure are 10 Omega , 20 Omega , 30 Omega and 60 Omega respectively . The emf and internal resistance of the cell are 15 V and 2.5 Omega respectively . If the galvanometer resistance is 80 Omega then the net current drawn from the cell will be

A cell to emf. E and internal resistance r supplies currents for the same time t through external resistance R_1 and R_2 respectively. If the heat produced in both cases is the same, then the internal resistance is given by :

A cell to emf. E and internal resistance r supplies currents for the same time t through external resistance R_1 and R_2 respectively. If the heat produced in both cases is the same, then the internal resistance is given by :

Three cells of emf 2.0 v, 1.8 V and 1.5 V are connected in series. Their internal resistances are 0.05 Omega, 0.7 Omega " and " 1 Omega respectively. If the battery is connected to an external resistor of 4 Omega via a very resistance ammeter, what would be the reading in the ammeter ?

Three cells of emf 2.0 v, 1.8 V and 1.5 V are connected in series. Their internal resistances are 0.05 Omega, 0.7 Omega " and " 1 Omega respectively. If the battery is connected to an external resistor of 4 Omega via a very resistance ammeter, what would be the reading in the ammeter ?

In the ciruit the cells E_1 and E_2 have emfs of 4V and 8V and internal resistance 0.5 Omega and 1.0 Omega, respectively. Calculate the current through 6 Omega resistance.

A Cell sends a current of 0.5 A through a 2 Omega resistance. If the resistance is increased by 5 Omega , the current falls to 0.25 A. Find the emf of the cell and its internal resistance.

When a resistance of 12 Omega is conencted with a cell of emf 1.5 V,0.1 A current flows through the resistance internal resistance of the cell is