Two wave are represented by the equations `y_(1)=asinomegat` ad `y_(2)=acosomegat` the first wave

Two waves are represented by the equations y_1=a sin omega t and y_2=a cos omegat . The first wave

Two wave are represented by equation y_(1) = a sin omega t and y_(2) = a cos omega t the first wave :-

The resultant intensity after interference of two coherent waves represented by the equation Y_(1)=a_(1)sin omega t and Y_(2)=a_(2)sin((pi)/(2)-omega t) will be proportional to

A wave is represented by an equation, Y=A coskxsinomegat , then

Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude

Two light waves are represented by y_(1)=a sin_(omega)t and y_(2)= a sin(omega t+delta) . The phase of the resultant wave is

Two waves represented as y_(1) = A_(1) sin omega t and y_(2) = A_(2) cos omega t superpose at a point in space. Find out the amplitude of the resultant wave at that point .

Two waves are given by y_(1)=asin(omegat-kx) and y_(2)=a cos(omegat-kx) . The phase difference between the two waves is -

Two waves are given by y_(1)=asin(omegat-kx) and y_(2)=a cos(omegat-kx) . The phase difference between the two waves is -