The resultant amplitude of a vibrating particle by the superposition of the two waves
`y_(1)=asin[omegat+(pi)/(3)]` and `y_(2)=asinomegat` is

The resultant ampiltude of a vibrating particle by the superposition of the two waves y_(1) = a sin ( omega t + (pi)/(3)) and y_(2) = a sin omega t is :

The amplitude of the vibrating particle due to superposition of two SHMs , y_(1)=sin (omega t+(pi)/(3)) and y_(2)=sin omega t is :

The resultant amplitude due to superposition of two waves y_1 =5 sin (wt -kx) and y_2 =-5 cos (wt -kx-150 ^@)

Two wave are represented by the equations y_(1)=asinomegat ad y_(2)=acosomegat the first wave

Two wave are represented by the equations y_(1)=asinomegat ad y_(2)=acosomegat the first wave

Two wave are represented by the equations y_(1)=asinomegat ad y_(2)=acosomegat the first wave

Two simple harmonic motions A and B are given respectively by the following equations. y_(1)=asin[omegat+(pi)/(6)] y_(2)=asin[omegat+(3pi)/(6)] Phase difference between the waves is

The phase difference between the waves y=acos(omegat+kx) and y=asin(omegat+kx+(pi)/(2)) is

The phase difference between the waves y=acos(omegat+kx) and y=asin(omegat+kx+(pi)/(2)) is

Two particle are executing SHMs .The equations of their motions are y_(1)=10"sin"(omegat+(pi)/(4)) " and "y_(2)=5 "sin"(omegat+(sqrt(3)pi)/(4)) What is the ratio of their amplitudes.