If `| vec a|=3,| vec b|=4` then a value of `lambda` for which ` vec a+lambda vec b` is perpendicular to ` vec a-lambda vec b` is : `9/(16)` (b) `3/4` (c) `3/2` (d) `4/3`

If |vec(a)|=3, |vec(b)|+4 , then for what value of 1 is (vec(a)+lambdavec(b)) perpendicular to (vec(a)-lambdavec(b)) ?

if vec a=2i+2j+3k,vec b=-i+2j+k and vcec=3i+j are such that vec a+lambdavec b is perpendicular vec c then find the value of lambda

if | vec a | = 3, | vec b | = 4, | vec a-vec b | = 5 then | vec a + vec b | =?

Let vec a,vec b, and vec c are vectors such that |vec a|=3,|vec b|=4 and |vec c|=5, and (vec a+vec b) is perpendicular to vec c,(vec b+vec c) is perpendicular to vec a and (vec c+vec a) is perpendicular to vec b. Then find the value of |vec a+vec b+vec c|

The value of lambda for two perpendicular vectors vec(A)=2vec(i)+lambdavec(j)+vec(k) and vec(B)=4vec(i)-2vec(j)-2vec(k) is :-

If |vec a|=3,|vec b|=4and the angle between aandb is 120^(@), then find the value of |4vec a+3vec b|

If vec a and vec b are two vectors such that |vec a|=4,|vec b|=3 and vec a*vec b=6. Find the angle between vec a and vec b

[[[(2vec a + vec b) vec cvec d] = lambda [vec with cvec d] + mu [vec bvec cvec d] hen lambda + mu is equal to

If |vec(a) | = 3, |vec(b)|= 4 and |vec(a)- vec(b)|=5 , then what si the value of |vec(a) + vec(b)| =?

The vector equation of the plane passing through the origin and the line of intersection of the planes vec rdot vec a=lambdaa n d vec rdot vec b=mu is a. vec rdot(lambda vec a-mu vec b)=0 b. vec rdot(lambda vec b-mu vec a)=0 c. vec rdot(lambda vec a+mu vec b)=0 d. vec rdot(lambda vec b+mu vec a)=0