In `Delta ABC, cos""((B+2C+3A)/(2))+ cos""((A-B)/(2))=`

Similar Questions

Explore conceptually related problems

In Delta ABC, cos""((3A+2B+C)/(2))+ cos""((A-C)/(2))=

Delta ABC, cos ((B + 2C + 3A) / (2)) + cos ((AB) / (2)) =

In Delta ABC,(cos 2A)/(a^2) - (cos2B)/(b^2) = ......

In a Delta ABC if (a+b)cos((B)/(2))=b(a+c)cos((C)/(2)) then prove that the triangle ABC is isosceles.

In Delta ABC if 2c cos^(2)((A)/(2))+2a cos^(2)((C)/(2))-3b=0. Prove that a,b,c are in AP

If A,B,C are the angles of a triangle ABC that cos((3A+2B+C)/(2))+cos((A-C)/(2))=

If in a triangle ABC,b cos^(2)((A)/(2))+a cos^(2)((B)/(2))=(3)/(2)c then a,c,b are:

In a Delta ABC, c cos ^(2)""(A)/(2) + a cos ^(2) ""(C ) /(2)=(3b)/(2), then a,b,c are in

IF in triangle ABC a cos ^2 ((C )/(2 )) c cos ^2 ((A) /(2 )) = (3 b)/(2) then the sides a,b,and c