The equation to the circle which touches the axis of `y` at the origin and passes through (3, 4) is `2(x^2+y^2)-3x=0` `3(x^2+y^2)-25 x=0` `4(x^2+y^2)-25y=0` `4(x^2+y^2)-25 x+10=0`

The equation of the circle which pass through the origin and cuts orthogonally each of the circles x^(2)+y^(2)-6x+8=0 and x^(2)+y^(2)-2x-2y-7=0 is

The circles whose equations are x^(2)+y^(2)+10x-2y+22=0 and x^(2)+y^(2)+2x-8y+8=0 touch each other. The circle which touch both circles at, the point of contact and passing through (0,0) is, 1) 9(x^(2)+y^(2))-15x-20y=0, 2) 5(x^(2)+y^(2))-18x-80y=0 3) 7(x^(2)+y^(2))-18x-80y=0, 4) x^(2)+y^(2)-9x-40y=0 ]]

The equation of the circle of radius 5 in the first quadrant which touches the x-axis and the line 3x-4y=0 is x^(2)+y^(2)-24x-y-25=0x^(2)+y^(2)-30x-10y+225=0x^(2)+y^(2)-16x-18y-64=0x^(2)+y^(2)-20x-12y+144=0

Find the equation of the line parallel to the line 3x-4y+2=0 and passing through the point (-2,5) .

The equation of the circle having the center on the line x+2y-3=0 and passing through the point intersection of the circles x^(2)+y^(2)-2x-4y+1=0andx^(2)+y^(2)-4x-2y+4=0 is x^(2)+y^(2)-6x+7=0x^(2)+y^(2)-3u-2y+4=0x^(2)+y^(2)-2x-2y+1=0x^(2)+y^(2)+2x-2y+4=0

Suppose a x+b y+c=0 , where a ,ba n dc are in A P be normal to a family of circles. The equation of the circle of the family intersecting the circle x^2+y^2-4x-4y-1=0 orthogonally is (a)x^2+y^2-2x+4y-3=0 (b)x^2+y^2-2x+4y+3=0 (c)x^2+y^2+2x+4y+3=0 (d) x^2+y^2+2x-4y+3=0

The equation of the circle passing through the origin and the points of intersection of the two circles x^(2)+y^(2)-4x-6y-3=0,x^(2)+y^(2)+4x-2y-4=0 is

Find the equation of the circle which cuts orthogonally the circle x^(2)+y^(2)6x+4y-3=0, passes through (3,0) and touches the axis of y.