A bomb at rest explodes into three parts of the same mass. The linear momenta of the two parts are `-2phati` and `p hati` Calculate the magnitude of momentum of third part .

A bomb at rest explodes into three parts of the same mass. The linear momentum of two parts are -2phat(i) and p hat(j) . The magnitude of momentum of third part is psqrt(x) . Find x.

A bomb at rest explodes into three parts of the same mass. The momentum of two parts are - 2 p hat(i) and p hat(j) . Find the magnitude of the momentum of the third part.

A bomb at rest explodes into 3 parts of the same mas. The momenta of the two parts are -2p hati and phatj . What is the magnitude of the momentum of the third part?

A bomb at rest explodes into three parts of the same mass the momenta of the two parts are - 2 p hati and p hat j The momentum of the third part will have a magnitude of :

A bomb at rest explodes into three parts of the same mass the momenta of the two parts are - 2 p hati and p hat j The momentum of the third part will have a magnitude of :

A block at rest explodes into 3 parts are -2phatj and phatj . Calculate the magnitude of the momentum of third part.

A bomb at rest explodes into three parts of the same mass. The momentum of the two parts are xhat(i) and -2 x hat(j) . The momentum of the third part will have a magnitude of

A bomb at rest explodes into three parts of the same mass. The momentum of the two parts are xhat(i) and -2 x hat(j) . The momentum of the third part will have a magnitude of

A bomb at rest explodes into three parts of the same mass. The momentum of the parts are 2Phati and Phatj The momentum of the third part will have a magnitude of: