A bus can be stopped by applying a retarding force F when it is moving with speed v on a level road. The distance covered by it before coming to rest is `s`. If the load of the bus increase by 50% because of passengers, for the same speed and same retarding force, the distance covered by the bus to come to rest shall be

A bus moving on a level road with a velocity v can be stopped at a distance of x by the application of a retarding force F The load on the bus is increased by 25% by boarding the passengers. Now if the bus is moving with the same speed and if the same retarding force is applied the distance travelled by the bus before it stops is .

2A car of 1000 kg moving with a velocity of 18 km//hr is stopped by the brake force of 1000 N. The distance covered by it before coming to rest is -

The same retarding force is applied to stop a train. IF the speed is doubled then the distance will be

Initially a car is moving with speed of 20 ms^(-1) and covers a distance of 100 m before it comes to rest. On making the initial speed of car 40 ms^(-1) keeping the acceleration same, the distance travelled by car before it comes to rest is

Initially a car is moving with speed of 20 ms^(-1) and covers a distance of 100 m before it comes to rest. On making the initial speed of car 40 ms^(-1) keeping the acceleration same, the distance travelled by car before it comes to rest is

A car moving with a velocity v is stopped within a distance x by applying a retarding force F. If the speed of the car is doubled, then the force required to stop the car with the same distance is

A car is moving at a speed of 18 km . It starts retarding uniformly at 1m/s and cover to rest. Find the distance travelled.

A retarding force is applied to stop motor car. If- the speed of the motor car is doubled, how much more distance will it cover before stopping under the same retarding force?