Home
Class 11
PHYSICS
1672cal of heat is given to one mole of ...

`1672cal` of heat is given to one mole of oxygen at `0^(@)C` keeping the volume constant. Raise in temperature is `(c_(p)=0cal//gm^(0)k and R=2cal//"mole"//K)`

Promotional Banner

Similar Questions

Explore conceptually related problems

1672 cal of heat is given to one mole of oxygen at 0^(@)C keeping the volume constant. Rise in temperature is (R = 2 cal/mole/ ""^(@) K)

Work done by 0.1 mole of a gas at 27°C to double its volume at constant pressure is (R = 2 cal/mol/K)

Work done by 0.1 mole of a gas at 27^@ C to double its volume at constant pressure is (use R=2 cal/mol ""^(@) C)

Work done by 0.1 mole of a gas at 27^(@)C to double its volume at constant pressure is (R=2" cal mol"^(-1).^(@)K^(-1))

If 50 cal of heat is supplied at constant pressure to the system containing 2 mol of an ideal monatomic gas, the rise in temperature is (R = 2 cal//mol-K)

Calculate the work done by 0.1 mole of a gas at 27^(@)C to double its volume at constant pressure (R = 2 cal mol^(-1)K^(-1))

Calculate the work done by 0.1 mole of a gas at 27^(@)C to double its volume at constant pressure (R = 2 cal mol^(-1)K^(-1))

3 moles of a monoatomic gas requires 45 cal heat for 5^(@)C rise of temperature at constant volume, then heat required for 5 moles of same gas under constant pressure for 10^(@)C rise of temperature is (R=2 cal//"mole"//^(@)K)

Five moles of oxygen gas is heated from 40°C to 70°C at constant pressure Heat given to the gas will be (given R 2 cal/mol K)

Five moles of oxygen gas is heated from 40°C to 70°C at constant pressure Heat given to the gas will be (given R=2 cal/mol K)