A body is fired with a velocity of magnitude `sqrt(gR) lt Vsqrt(2gR)` at an angle of `30^(@)` with the radius vector of earth. If at the highest point the speed of the body is `V//4`, the maximum height attained by the body is equal to:

A body is fired with a velocity of magnitude sqrt(gR) lt V lt sqrt(2gR) at an angle of 30^(@) with the radius vector of earth. If at the highest point the speed of the body is V//4 , the maximum height attained by the body is equal to:

A body is fired with a velocity of magnitude sqrt(gR)ltVltsqrt(2gR) at an angle of 30^@ with the radius vector of the earth. If at the highest point, the speed of the body is V//4 , the maximum height attained by the body is equal to

A body is fired with a velocity of magnitude sqrt(gR)ltVltsqrt(2gR) at an angle of 30^@ with the radius vector of the earth. If at the highest point, the speed of the body is V//4 , the maximum height attained by the body is equal to

A body is projected vertically upwards from the surface of earth with a velocity equal to half of escape speed. What is the maximum height attained by the body ?

A body is projected vertically upward with the velocity v=3hati+4hatjms^(-1) . The maximum height attained by the body is ( g=10ms^(-2) ).

If the velocity of centre of mass of a rolling body is V then velocity of highest point of that body is

A rigid body of moment of inertial I is projected with velocity V making an angle of 45^(@) with horizontal. The magnitude of angular momentum of the projectile about the point of projection when the body is its maximum height is given by (IV^(3))/(2sqrt(2)gR^(2)) where R is the radius of the rigid body. the ridid body is

A body is thrown from the surface of the earth with velocity (gR_(e))//12 , where R_(e) is the radius of the earth at some angle from the vertical. If the maximum height reached by the body is R_(e)//4 , then the angle of projection with the vertical is