In YDSE, two wavelengths of `500 nm and 700 nm` are used. What is the minimum their maxima coincide ? Take `D//d = 10^(3)`, symbols have standard meaning.

In a young's double slit experiment, two wavelength of 500 nm and 700 nm were used. What is the minimum distance from the central maximum where their maximas coincide again ? Take D//d = 10^(3) . Symbols have their usual meanings.

In a young's double slit experiment, two wavelength of 500 nm and 700 nm were used. What is the minimum distance from the central maximum where their maximas coincide again ? Take D//d = 10^(3) . Symbols have their usual meanings.

In a young's double slit experiment, two wavelength of 500 nm and 700 nm were used. What is the minimum distance from the central maximum where their maximas coincide again ? Take D//d = 10^(3) . Symbols have their usual meanings.

In a Young's double slit experiment, two wavelengths of 500nm and 700 nm were used. What is the minimum distance from the central maximum where their maxima's coincide again? (Take D/d=1000) . Symbols have their usual meanings

In YDSE wavelength of light used is 500 nm and slit width is 0.05 mm . then the angular fringe width will be.

In YDSE wavelength of light used is 500 nm and slit width is 0.05 mm . then the angular fringe width will be.

In YDSE, bichromatic light of wavelengths 400 nm and 560 nm are used. The distance between the slits is 0.1 mm and the distance between the plane of the slits and the screen is 1m. The minimum distance between two successive regions of complete darkness is

Light used in a Young's double-slit experiment consists of two wavelengths 450 nm and 720 nm. In the interference pattern, eighth maximum of the first coincides with the mth maximum of the second. What is m?

In YDSE bi-chromatic light of wavelengths 400 nm and 560 nm are used. The distance between the slits is 0.1 mm and the distance between the plane of the slits and the screen is 1.0m. The minimum distance between two successive regions of complete darkness is

A beam of light consisting of two wavelength 800 nm and 600 nm is used to obtain the interference fringes in YDSE on a screen held 1.4 m away. If the two slits are separated by 0.28 mm , calculate the least distance from thecentral bright maximum, where the bright fringes of the two waveength coincide.