Calculate the value of `Lambda_(m) ^prop` for `SrCl_(2)` in water at `25^(@)C` from the following data `:`
`{:(Conc. (mol//l t),,0.25,,1),(Lambda_(m)(Omega^(-1)cm^(2)mol^(-1)),,260,,250):}`

Calculate the value of Lambda_(m) ^prop for SrCl_(2) in water at 25^(@)C from the following data : {:(Conc. (mol//l t),,0.5,,1),(Lambda_(m)(Omega^(-1)cm^(2)mol^(-1)),,260,,250):}

Find ^^_(m)^(oo) ("in" Omega^(-1) cm^(2) mol^(-1)) for strong electroyte AB_(2) in water at 25^(@) form the following data. |{:("Conc".C("mole"//L),0.25,1),(^^_(m)(W^(1-)cm^(2)//mol),160,150):}|

Find ^^_(m)^(oo) ("in" Omega^(-1) cm^(2) mol^(-1)) for strong electroyte AB_(2) in water at 25^(@) form the following data. |{:("Conc".C("mole"//L),0.25,1),(^^_(m)(W^(1-)cm^(2)//mol),160,150):}|

The following data is obtained at 25^(@)C , for an aqueous solution of NaCl {:("Conc.(in molarity)",0.25,0.64),(A_(m)("in" ohm^(-1)m^(2)"mol"^(-1)),0.025,0.019):} At 25^(@)C , the molar conductivity of 0.49M aqueous NaCl solution is:

Calculate the dissociation constant of water at 25^(@)C from the following data. Specific conductance of H_(2)O = 5.8 xx 10^(-8) mho cm^(-1), lambda_(H^(+))^(oo) = 350.0 and lambda_(OH^(-))^(oo) = 198.0 mho cm^(2)

Calculate the dissociation constant of water at 25^(@)C from the following data. Specific conductance of H_(2)O = 5.8 xx 10^(-8) mho cm^(-1), lambda_(H^(+))^(oo) = 350.0 and lambda_(OH^(-))^(oo) = 198.0 mho cm^(2)