The successive ionization enthalpies of an element M are 5.98, 18.82, 28.44, 119.96, 153.77, ....eV/atm. What is the formula of chloride of M?

The successive ionisation enthalpies of an element M are 5.98, 18.82, 28.44, 119.96, 153.77, ...... e V atom What is the formula of chloride of M?

Successive ionisation potentials of an element M are 8.3, 25.1, 37.9, 259.3 and 340.1ev. The formula of its bromide is

Successive ionisation potentials of an element M are 8.3,25.1,37.9,259.3 and 340.1 ev. The formula of its bromide is

The values of IE_1 , IE_2 , IE_3, IE_4 and IE_5 of an element are 5.98, 18.82, 28.44, 120 and 153.8 eV respectively. The element is likely to be

The values of IE_1 , IE_2 , IE_3, IE_4 and IE_5 of an element are 5.98, 18.82, 28.44, 120 and 153.8 eV respectively. The element is likely to be

The ionization constant of ammonium hydroxide is 1.77xx10^(-5) at 298 K. Calculate the hydrolysis ammonium chloride and pH of 0.04M ammonium chloride solution.

The energy required to remove an electron from the outermost shell of an isolate gaseous atom is known as IE_(1) of that atom. Similarly, the enrgy required for the removal of the electron from the unipositive ion, diapositive ion and tripositive ion are known as IE_(2),IE_(3) and IE_(4) respectively, and are called successive ionisation energies. The magnitude of the charge depends on the size of the orbital of electron. Electrons in smaller orbitals are on average close with each other and have more repulsion. Thus for Be(2s^(2)) , the IE_(1) and IE_(2) are 9.3 and 18.2 eV "atom"^(1) , whereas for Ca(4s^(2)) , the values are 6.1 and 11.9 eV . Four elemensts have the following first ionization energies in KJmol^(-1): 762, 709, 59 and 558 . The elements are Ca, Ge . In and Sn (not in order). Which of these elements has the ionisation energy of 762 KJ mol^(-1) ?