In `DeltaABC`,
seg `AD bot` seg `BC`,
`DB=3CD`.
Prove that `2AB^(2)=2AC^(2)+BC^(2)`.

In Delta ABC, "seg" AD bot "seg" BC, DB = 3CD . Prove that: 2 AB^(2) = 2AC^(2) + BC^(2)

In Delta ABC seg AD perp seg BC,DB=3CD Prove that 2AB^(2)=2AC^(2)+BC^(2)

See the given figure. In DeltaABC," seg "ADbot" seg "BC. Prove that: AB^(2)+CD^(2)=BD^(2)+AC^(2)

In the given figure, the of a Delta ABC , interesects BC at D such DB=3CD . Prove that 2AB^(2)=2AC^(2)+BC^(2)

The perpendicular from A on side BC of a DeltaABC intersects BC at D such the DB = 3 CD . Prove that 2 AB^(2)=2AC^(2)+BC^(2)

The perpendicular drawn from A on sides BC of a Delta ABC intersects BC at D such that DB = 3CD .Prove that 2AB^(2)=2AC^(2)+BC^(2) .

The perpendicular from A on side BC of a DeltaABC meets BC at D such that DB = 3CD .Prove that 2AB^(2)=2AC^(2)+BC^(2) .

The perpendicular AD on the base BC of a triangleABC intersects BC at D, so that DB=3CD. Prove that 2AB^(2)= 2AC^(2)+BC^(2)

In Delta ABC , AD bot BC and AD^(2)= BD xx CD . Prove that AB^(2) + AC^(2) = (BD + CD)^(2)