If the distance 's' travelled by a body in time 't' is given by `s = a/t + bt^2` then the acceleration equals

If the distance S travelled by a particle in time t is given by s = t^(2) - 2t + 5 then its acceleration is

If the distance s travelled by a particle in time t is given by s=t^2-2t+5 , then its acceleration is

If the distance s travelled by a particle in time t is s=a sin t +b cos 2t , then the acceleration at t=0 is: a) a b) -a c) 4a d) -4b

If the distance s travelled by a particle in time t is s=a sin t +b cos 2t , then the acceleration at t=0 is

The distance s feet travelled by a particle in time t second is given by s = t^3 - 6t^2 - 4t -8 . It acceleration vanishes at time t =

The distance s moved by a particle in time t is given by s=t^(3)-6t^(2)+6t+8 . When the acceleration is zero, the velocity is ………..

If the displacement in time t of a particle is given by s = ae^(t) + be^(-t) . Then the acceleration is equal to

The distance (s) travelled by a body in time (t) is given by s = ut + (1)/(2)at^(2) . How is the formula modified when (i) body starts from rest , (ii) motion of body is uniform.