In `triangleABC` (not shown), `angleABC=60^(@) and ACbotBC`. If `AB=x`, then what is the area of `triangleABC`, in terms of x?

In triangleABC (not shown), AC bot BC ad cos angleABC=(12)/(13) . What is the value of tan angleABC ?

In triangleABC, AB=10cm, angleA=45^(@) and angleC=60^(@) . Find BC.

In triangleABC, AB=10cm, angleA=45^(@) and angleC=60^(@) . Find BC.

If, in triangleABC, a= sqrt(2), b= sqrt(3), c = sqrt(5) , then the area of triangleABC is

In angleABC, angleABC =90^@ , AB = 5 cm, BC = 12 cm. Find the length of the circumradius of triangleABC .

In triangleABC , if AD is the median and angleABC = 90^@ , then AC^2 =

In triangleABC , P is the mid-point of BC and Q is the mid-point of AP. Find the ratio of the area of triangleABQ and the area of angleABC . The following are the steps involved in solving the above problem. A) We know that a a median of a triangle divides a triangle into two triangles of equal area. B) rArr Ar(triangleABP) =1/2[Ar(triangleABC)] C) Ar(triangleABQ)=1/2[Ar(triangleABP)]=1/4[Ar(triangleABC)] D) rArr(triangleABQ):Ar(triangleABC)=1:4

In a triangleABC, A=30^(@), B=60^(@) . Find the other angle C

In triangleABC , angleA= 60^(@) prove that BC^(2)= AB^(2)+AC^(2)- AB . AC